-6x^2-26x-20=0

Solution for -6x^2-26x-20=0 equation:

-6x^2-26x-20=0

a = -6; b = -26; c = -20;
Δ = b2-4ac
Δ = -262-4·(-6)·(-20)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*-6}=\frac{12}{-12}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*-6}=\frac{40}{-12}
=-3+1/3
$